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WBJEE 2018 Math Solved Paper
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© examsnet.com
Question : 71
Total: 75
Let I =
1
∫
0
x
3
c
o
s
3
x
2
+
x
2
dx. Then
−
1
2
<
I
<
1
2
−
1
3
<
I
<
1
3
−
1
<
I
<
1
−
3
2
<
I
<
3
2
Validate
Solution:
−
1
<
c
o
s
3
x
<
1
−
x
3
<
x
3
c
o
s
3
x
<
x
3
−
x
3
x
2
<
−
x
3
x
<
−
x
3
2
+
x
2
<
x
3
c
o
s
3
x
2
+
x
2
<
x
3
2
+
x
2
<
x
3
x
<
x
3
x
2
taking integration from 0 to 1
⇒
1
∫
0
−
x
2
d
x
<
I
<
1
∫
0
x
2
d
x
⇒
(
−
x
3
3
)
0
1
<
I
<
(
x
3
3
)
0
1
⇒
−
1
3
<
I
<
1
3
So, (ABCD)
© examsnet.com
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