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WBJEE 2019 Chemistry Solved Paper

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Question : 18 of 40

Marks: +1, -0

For a vander Waal’s gas, the term

\left(\frac{ab}{v^2}\right)

represents some

Pressure
Energy
Critical density
Molar mass

Solution:

(B)

Term

\left(\frac{ab}{v^2}\right)

represent energy per mole of gases.

Unit of a (Vander wal’s constant) =

\frac{\mathrm{atmliter}^2}{\mathrm{mole}^2}

Unit of b (Vander wals’s constant) =

\frac{\mathrm{liter}}{\mathrm{mole}}

V = volume of gas per mole =

\frac{\mathrm{liter}}{\mathrm{mole}}

So

\frac{ab}{v^2}(\text{Unit}) = \frac{ \frac{\mathrm{atmliter}^2}{\mathrm{mole}^2} \times \frac{\mathrm{liter}}{\mathrm{mole}} }{ \left( \frac{\mathrm{liter}}{\mathrm{mole}} \right)^2 }

=

\left( \frac{\mathrm{atmilter}}{\mathrm{mole}} \right)

It is unit of energy per mole.

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