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WBJEE 2019 Math Solved Paper
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© examsnet.com
Question : 19
Total: 75
General solution of
(
x
+
y
)
2
d
y
d
x
=
a
2
, a ≠ 0 is (c is arbitrary constant)
x
a
=
tan
y
a
+ c
tanxy = c
tan(x + y) = c
tan
y
+
c
a
=
x
+
y
a
Validate
Solution:
(D)
d
y
d
x
=
a
2
(
x
+
y
)
2
put x + y = t ⇒ 1 +
d
y
d
x
=
d
t
d
x
⇒
d
t
d
x
=
1
+
a
2
t
2
⇒
t
2
(
t
2
+
a
2
)
dt = dx
⇒ dt –
a
2
(
t
2
+
a
2
)
dt = dx
⇒ t –
a
tan
–
1
t
a
+ c = x ⇒ y + c =
a
tan
–
1
y
+
a
a
⇒ tan
y
+
c
a
=
x
+
y
a
© examsnet.com
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