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WBJEE 2020 Physics Solved Paper
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© examsnet.com
Question : 30
Total: 40
A thin convex lens is placed just above an empty vessel of depth 80 cm. The image of a coin kept at the bottom of the vessel is thus formed 20 cm above the lens. If now water is poured in the vessel up to a height of 64 cm, what will be the approximate new position of the image. Assume that refractive index of water is 4/3.
21.33 cm above the lens
6.67 cm below the lens
33.67 cm above the lens
24 cm above the lens
Validate
Solution:
u = – 80 cm v = + 20 cm
1
f
=
1
v
−
1
u
=
1
20
+
1
80
=
5
80
f
=
16
cm
u
′
=
16
+
64
×
3
4
=
64
cm
1
16
=
1
v
+
1
64
∴
1
v
=
1
16
−
1
64
=
3
64
v = 21.33 above the lens
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