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WBJEE 2021 Physics and Chemistry Solved Paper

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Category II (Q31 to Q 35)

Carry 2 marks each and only one option is correct. In case of incorrect answer or any combination of more than one answer, ½ mark will be deducted

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Question : 35

Total: 80

For a plane eletromagnetic wave, the electric field is given by

=90‌sin(0.5×103x+1.5×1011t) k.v∕m. The corresponding magnetic field

will be

→
B
=3×10−7‌sin(0.5×103x+1.5 ×1011t)‌
^
i
‌T
→
B
=3×10−7‌sin(0.5×103x+1.5 ×1011t)‌
^
j
‌T
→
B
=27×109‌sin(0.5×103x+1.5 ×1011t)‌
^
j
‌T
→
B
=3×10−7‌sin(0.5×103x+1.5 ×1011t)‌
^
k
‌T

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