Xavier Aptitude Test 2012 Paper

(b) Let l and b be the length and breadth of the plot.
Perimeter of the remaining land
=2[2b−l+l−b]=2b
Perimeter of original land =2(l+b)
∴ Given

2b

2(l+b)

=

3

8

8b=3l+3b
5b=3l
This can be possible if we choose
l=5 and b=3
∴ Area of land =15 sq. units
cost of land =1000×15
Now, selling price of small and big squares are 9×1200 and
4×1150 respectively.Let be sells the remaining land at $x per sq. ft.
Hence,
2x=1100
x=550
Hence option (b)