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Xavier Aptitude Test 2021 Paper

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Question : 11 of 100

Marks: +1, -0

On the bank of the pristine Tunga river, a deer and a tiger are joyfully playing with each other. The deer notices that it is 40 steps away from the tiger and starts running towards it. At the same time, the tiger starts running away from the deer. Both run on the same straight line. For every five steps the deer takes, the tiger takes six. However, the deer takes only two steps to cover the distance that the tiger covers in three. In how many steps can the deer catch the tiger?

200
To solve this, the length of a deer’s step must also be given
120
360
320

Solution:

Let speed of deer

= 5\ \text{steps per second}

and speed of tiger

= 6\ \text{steps per second}

Let deer cover

1\ \text{m}

in a step ⇒ tiger covers

\frac{2}{3}\ \text{m}

in a step

Hence speed of deer

= 5\ \text{m per second}

and speed of tiger

= 6 \times \frac{2}{3}\ \text{m per second}

=

4\ \text{m per second}

Hence time taken by a deer to catch tiger

= 40\ \text{seconds}

Distance traveled by deer in

40\ \text{seconds} = 5 \times 40 = 200\ \text{steps}

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