Xavier Aptitude Test 2025 Paper

Considering statement 1: We can only get one of the sides length of the land. But that is not sufficient to get the area.Considering statement 2:We are given the diagonal length.With this information and the perimeter it is not possible to find the area of land.Considering both 1 and 2 statements.Now we have two right angle triangles. We know the hypotenues of both the triangles.$$\begin{aligned} & A B^{2}+A D^{2}=B D^{2} \\ & 110^{2}+A B^{2}=255^{2} \\ & \mathrm{AB} \approx 230 \end{aligned}$$Let $\mathrm{DC}=\mathrm{x}, \mathrm{BC}=700-110-230-\mathrm{x}=360-\mathrm{x}$.$$x^{2}+(360-x)^{2}=255^{2}$$Upon solving this we get $\mathrm{x}=180 \pm \frac{15}{\sqrt{2}}$$$360-x=180 \pm \frac{15}{\sqrt{2}}$$Area of triangle $\mathrm{ABD}=\frac{1}{2} \cdot 110 \cdot 230=12650$Area of triangle $\mathrm{BDC}=\frac{1}{2}\left(180+\frac{15}{\sqrt{2}}\right)\left(180-\frac{15}{\sqrt{2}}\right)=16143.75$So, total area $=12650+16143.75=28793.75$Cost $=28793.75 \times 400=$ Rs. 1,15,17,500.So, option C is the answer.