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TGTET Paper 1 Exam 23 Jul 2017 Paper

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Question : 100 of 150
Marks: +1, -0
If the perimeter of an equilateral triangle is 24 cm, then its altitude is (in cm) ______
Solution:  
Concept:
Understanding the properties of an equilateral triangle and using the relationship between its perimeter, side length, and altitude.
Formulas Used:
Perimeter of an equilateral triangle = 3×side3 \times side
Altitude of an equilateral triangle = 32×side\frac{\sqrt{3}}{2} \times side
Explanation:
We are given that the perimeter of an equilateral triangle is 24 cm.
Let the side length of the equilateral triangle be aa.
The perimeter is given by 3a3a.
So, 3a=243a = 24 cm.
Dividing by 3, we get the side length a=243=8a = \frac{24}{3} = 8 cm.
Now, we need to find the altitude (height) of the equilateral triangle.
The formula for the altitude of an equilateral triangle is h=32×ah = \frac{\sqrt{3}}{2} \times a.
Substituting the value of a=8a = 8 cm into the formula:
h=32×8h = \frac{\sqrt{3}}{2} \times 8
h=43h = 4\sqrt{3} cm.
Answer:
The altitude of the equilateral triangle is 434\sqrt{3} cm.
The correct option is D.
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