Concept:The number of integers between two consecutive perfect squares $n^2$ and $(n+1)^2$ is $2n$.Explanation:We are asked to find the number of integers that lie strictly between $(35)^2$ and $(36)^2$.First, let's calculate the values of these squares:$(35)^2 = 35 \times 35 = 1225$$(36)^2 = 36 \times 36 = 1296$We need to find the number of integers between 1225 and 1296. These integers are 1226, 1227, ..., 1295.To find the count of these integers, we can use the formula: Number of integers = (Last integer) - (First integer) + 1.In this case, the first integer is 1226 and the last integer is 1295.Number of integers = $1295 - 1226 + 1 = 69 + 1 = 70$.Alternatively, using the general concept for consecutive squares: For squares $n^2$ and $(n+1)^2$, the number of integers between them is $(n+1)^2 - n^2 - 1 = n^2 + 2n + 1 - n^2 - 1 = 2n$.Here, $n = 35$. So, the number of integers is $2 \times 35 = 70$.Answer:70