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CBSE Class 10 Math 2023 Delhi Set-1 Solved Paper

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Question : 33 of 38
Marks: +1, -0
(A) DD is a point on the side BCBC of a triangle ABCABC such that ∠ADC=∠BAC\angle ADC = \angle BAC, prove that CA2=CB⋅CDCA^2 = CB \cdot CD
OR
(B) If ADAD and PMPM are medians of triangles ABCABC and PQRPQR, respectively where △ABC∼△PQR\triangle ABC \sim \triangle PQR, prove that ABPQ=ADPM\frac{AB}{PQ} = \frac{AD}{PM}.
Solution:     👈: Video Solution
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