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CBSE Class 10 Science 2015 Term I Set 2

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Question : 14
Total: 36
In the given electric circuit if the current flowing through 3Ω resistor is 1A, find the voltage of the battery and the current I drawn from it.
Solution:  
E‌=?
I‌=?
R2‌=3Ω
I2‌=1A(‌ Current flowing through ‌R2)
V2‌=I2R2=1×3=3‌ volts ‌
Resultant resistance of R2 and R3 is R′.
‌
1
R′
‌=‌
1
R2
+‌
1
R1
=‌
1
3
+‌
1
6
=‌
2+1
6
=‌
3
6
=‌
1
2

R′‌=2Ω
V′‌=V2=3‌ volts (Voltage across ‌R′)
I′‌=?
I′‌=‌
V′
R′
=‌
3
2
A=1.5A
I′‌=I=1.5A
Resultant resistance in the circuit =R
R‌=R1+R′=2+2=4Ω
I‌=‌
3
2
A
V‌=?
V‌=IR=‌
3
2
×4=6‌ volts ‌
⇒‌‌E‌=V=6‌ volts ‌
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