CBSE Class 10 Science 2019 Delhi Set 1

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Question : 17
Total: 28
Write the chemical formula and name of the compound which is the active ingredient of all alcoholic drinks. List its two uses. Write chemical equation and name of the product formed when this compound reacts with-
(i) sodium metal
(ii) hot concentrated sulphuric acid
OR
What is methane? Draw its electron dot structure. Name the type of bonds formed in this compound. Why are such compounds:
(i) poor conductors of electricity? and
(ii) have low melting and boiling points? What happens when this compound burns in oxygen?
Solution:  
The name of the ingredient of the alcoholic drink is ethanol.
Its formula is C2H5OH.
Two uses of ethanol (C2H5OH) are :
(a) It is used as a solvent in various industries.
(b) It is also used as an antiseptic solution.
(i) Reaction of ethanol with sodium metal
C2H5OH
Ethanol
+Na
C2H5ONa+H2
Sodium ethanoate

(ii) Reaction of ethanol with conc. H2SO4
C2H5OH
Ethanol
Conc.
H2SO4
CH2
Ethene
=CH2+H2O

Methane is a hydrocarbon formed by the combination of carbon with hydrogen. Its molecular formula is CH4. It is a main green house gas. The type of bond formed in methane is covalent bond.
Electron dot structure of methane (CH4) :
(i) Covalent compounds are poor conductors of electricity because it has no free electrons to conduct electricity. Moreover this compound is formed by sharing of electrons. So no electron is available for the conduction.
(ii) They have weak forces of attraction between them so less energy is required to break the force of binding. Thus they have low melting and boiling points.
When this compound burns in oxygen, combustion reaction takes place.
CH4
O2
CO2
+H2O
+ Heat
+ light
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