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Question : 11
Total: 12
A 6 cm tall object is placed perpendicular to the principal axis of a concave mirror of focal length 30 cm . The distance of the object from the mirror is 45 cm . Use mirror formula to determine the position, nature and size of the image formed. Also draw labelled ray diagram to show the image formation in this case.
OR
An object6 cm in size is placed at 50 cm in front of a convex lens of focal length 30 cm .
At what distance from the lens should a screen be placed in order to obtain a sharp image of the object? Find the nature and size of the image. Also draw labelled ray diagram to show the image formation in this case.
OR
An object
At what distance from the lens should a screen be placed in order to obtain a sharp image of the object? Find the nature and size of the image. Also draw labelled ray diagram to show the image formation in this case.
Solution:
Given, Height of the object h 0 = 6 cm
Focal length,f = − 30 cm
Object distance,u = − 45 cm
Image distance,v = ?
Height of image,h i = ?
We have,
=
+
=
+
+
=
=
v = − 90 cm
Also, we have
m =
=
=
= − 2
h i = − 12 cm .
Image is real and inverted.
Height of objecth o = + 6 cm Object distance, u = − 50 cm Focal length, f = + 30 cm ( C ) and focus ( F ′ ) .
Using lens formula,
=
−
=
+
=
−
=
=
∴ Image distance, v = + 75 cm
=
=
h i =
= − 9 cm
Hence, image formed is virtual, erect and magnified.
Focal length,
Object distance,
Image distance,
Height of image,
We have,
Also, we have
Image is real and inverted.
OR
Height of object
Formation of image by a convex lens when the object is placed between its optical centre
Using lens formula,
Hence, image formed is virtual, erect and magnified.
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