CBSE Class 10 Science 2020 Delhi Set 2

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Question : 8
Total: 10
(a) State the relation correlating the electric current flowing in a conductor and the voltage applied across it. Also draw a graph to show this relationship.
(b) Find the resistance of a conductor if the electric current flowing through it is 0.35 A when the potential difference across it is 1.4V.
Solution:  
(a) The ohm's law states that the current carrying in a conductor is directly proportional to the voltage applied across the ends of the conductor, keeping the resistance constant.
Circuit Diagram
According to ohm's law; VI
Mathematically; V=
where, V= Voltage applied in volts
I= Current flowing in circuit in amperes.
R= Resistance of conductor (proportionality constant)
Graphically; slope of will determine resistance of conductor.
(b) Given, current flowing through conductor
(I) =0.35A
Potential difference across conductor (V) =1.4V
We know, according to ohm's law, V=IR
1.4V=(0.35A)×R
R=(
1.4V
0.35A
)
=4

Therefore, resistance of conductor is 4 ohms.
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