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Question : 47
Total: 60
An object of height 4 cm is kept at a distance of 30 cm from the pole diverging mirror. If the focal length of the mirror is 10 cm , the height of the image formed is
Solution:
Explanation: Height of the object h = 4 cm
Object distance,u = − 30 cm
Focal length,f = 10 cm (Diverging mirror)
Using mirror formula,
1 ∕ v + 1 ∕ u = 1 ∕ f
u ∕ v = u ∕ f − 1
= ( − 30 ∕ 10 ) − 1
= 4
Magnification,m = image height/Object height = − ( v ∕ u )
= 1 ∕ 4
Image height= h ∕ 4 = 4 ∕ 4 = 1 cm
Object distance,
Focal length,
Using mirror formula,
Magnification,
Image height
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