CBSE Class 10 Science 2022 Outside Delhi Term II Set 1

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Question : 7
Total: 15
Consider the carbon compounds having following molecular formula:
(i) C3H6 (ii) C3H8 (iii) C4H6 (iv) C6H6 (v) C6H12
(a) State the number of double covalent bonds present in C3H6.
(b) Write the formula of first member of the homologous series to which the carbon compound C4H6 belongs.
(c) Which one of the above compounds forms ring structure of carbon atoms?
(d) Identify, which of the above compounds, is a member of alkane series.
Solution:  
(a) One double bond. (C3H6. Lewis structure contains three carbon atoms bonding with six hydrogen atoms, all these are bonded with the 7 single bonds and 1 double bond).
(b) C4H6 is an alkyne,
The alkynes comprise a series of carbonand hydrogen-based compounds that contain at least one triple bond. The group of compounds is a homologous series with the general molecular formula of CnH2n 2, where n equals to any integer greater than one. Thus, the first member of this homologous series is ethyne (C2H2).H CCH
(c) C6H6 (Benzene) will form the ring
The structure has a six-carbon ring which is represented by a hexagon and it includes 3-alternate double bonds.
(d) C3H8 is an alkane as it has each carbon bonded to four other atoms through single covalent bonds and follow general formula CnH2n+2
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