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Question : 7
Total: 15
Consider the carbon compounds having following molecular formula:
(i)C 3 H 6 (ii) C 3 H 8 (iii) C 4 H 6 (iv) C 6 H 6 (v) C 6 H 12
(a) State the number of double covalent bonds present inC 3 H 6 .
(b) Write the formula of first member of the homologous series to which the carbon compoundC 4 H 6 belongs.
(c) Which one of the above compounds forms ring structure of carbon atoms?
(d) Identify, which of the above compounds, is a member of alkane series.
(i)
(a) State the number of double covalent bonds present in
(b) Write the formula of first member of the homologous series to which the carbon compound
(c) Which one of the above compounds forms ring structure of carbon atoms?
(d) Identify, which of the above compounds, is a member of alkane series.
Solution:
(a) One double bond. ( C 3 H 6. Lewis structure contains three carbon atoms bonding with six hydrogen atoms, all these are bonded with the 7 single bonds and 1 double bond).
(b)C 4 H 6 is an alkyne,
The alkynes comprise a series of carbonand hydrogen-based compounds that contain at least one triple bond. The group of compounds is a homologous series with the general molecular formula ofC n H 2 n − 2 , where n equals to any integer greater than one. Thus, the first member of this homologous series is ethyne ( C 2 H 2 ) . H − C ≡ C − H
(c)C 6 H 6 (Benzene) will form the ring
The structure has a six-carbon ring which is represented by a hexagon and it includes 3-alternate double bonds.C 3 H 8 is an alkane as it has each carbon bonded to four other atoms through single covalent bonds and follow general formula C n H 2 n + 2
(b)
The alkynes comprise a series of carbonand hydrogen-based compounds that contain at least one triple bond. The group of compounds is a homologous series with the general molecular formula of
(c)
The structure has a six-carbon ring which is represented by a hexagon and it includes 3-alternate double bonds.
(d)
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