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Question : 1
Total: 7
Consider the following molecular formulae of carbon compounds:
(i)CH 3 COOH
(ii)CH 3 OH
(iii)C 2 H 6
(iv)C 3 H 4 C 4 H 8
(a) Which one of these compounds belongs to homologous series of alcohols?
(b) Identify the compound having triple bond between carbon - carbon atoms.
(c) Write the molecular formula of the first member of the homologous series to whichCH 3 COOH
(d) Write the general formula of the series to which the compoundC 4 H 8
(i)
(ii)
(iii)
(iv)
(a) Which one of these compounds belongs to homologous series of alcohols?
(b) Identify the compound having triple bond between carbon - carbon atoms.
(c) Write the molecular formula of the first member of the homologous series to which
(d) Write the general formula of the series to which the compound
Solution:
(a) CH 3 OH R − OH
(b)C 3 H 4
Lewis Structure ofC 3 H 4
H −
− C ≡ C − H
(c) Ethanoic acid is a member of homologous series with general formulaC n H 2 n + 1 COOH HCOOH
(d) The general formula for alkenes can be written asC n H 2 n ′ n = 2 , 3 , 4 C 4 H 8
(b)
Lewis Structure of
(c) Ethanoic acid is a member of homologous series with general formula
(d) The general formula for alkenes can be written as
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