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Question : 30
Total: 39
(A) Define the following terms in the context of a diverging mirror:
(i) Principal focus
(ii) Focal length
Draw a labelled ray diagram to illustrate your answer.
OR
(B) An object of height10 cm is placed 25 cm away from the optical centre of a converging lens of focal length 15 cm . Calculate the image-distance and height of the image formed.
(i) Principal focus
(ii) Focal length
Draw a labelled ray diagram to illustrate your answer.
OR
(B) An object of height
Solution:
(A) (i) The point of the principle axis from where all the incident rays appear to diverge from behind the mirror, is called principle focus of the diverging mirror.
(ii) The distance between the pole of the mirror and its principal focus is called focal length.O = + 10 cm
Focal length,f = + 15 cm
Object distance,u = − 25 cm
Image distance,v = ?
Image height,I = ?
Using lens formula,
=
−
=
−
Or,
=
−
=
v =
Also,
=
Hence,
=
I = ( − 1.5 ) × 10 = 15 cm
Height of image is15 cm , inverted.
(ii) The distance between the pole of the mirror and its principal focus is called focal length.
(B) Object height,
Focal length,
Object distance,
Image distance,
Image height,
Using lens formula,
Or,
Also,
Hence,
Height of image is
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