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Question : 10
Total: 10
(A) Write the chemical equation for the following:
(i) Combustion of methane
(ii) Oxidation of ethanol
(iii) Hydrogenation of ethene
(iv) Esterification Reaction
(v) Saponification Reaction
OR
(B) (i) Draw two structural isomers of butane.
(ii) Draw the structures of propanol and propanone.
(iii) Name the third homologue of:(a) alcohols(b) aldehydes
(iv) Name the following:
(i) Combustion of methane
(ii) Oxidation of ethanol
(iii) Hydrogenation of ethene
(iv) Esterification Reaction
(v) Saponification Reaction
OR
(B) (i) Draw two structural isomers of butane.
(ii) Draw the structures of propanol and propanone.
(iii) Name the third homologue of:(a) alcohols(b) aldehydes
(iv) Name the following:
(v) Show the covalent bond formation in nitrogen molecule.
Solution:
(A) (i) Combustion of methane:
CH 4 + 2 O 2 → CO 2 + 2 H 2 O
(ii) Oxidation of ethanol:
C 2 H 5 OH + 3 O 2 → 2 CO 2 + 3 H 2 O
(iii) Hydrogenation of ethene:
C 2 H 4 + H 2 → C 2 H 6
(iv) Esterification reaction: Carboxylic acid + Alcohol→
For example:
CH 3 COOH + C 2 H 5 OH → CH 3 COOC 2 H 5 + H 2 O
(v) Saponification reaction:
Ester+ NaOH →
For example:
C 2 H 5 COOCH 3 + NaOH → C 2 H 5 COONa + CH 3 OH C 4 H 10 C 3 H 7 OH ( − OH )
(b) The third homologue of aldehydes is propanal, with the chemical formulaC 3 H 6 O ( C = O )
(iv) (a) Benzene
(b) 'But-1-ene'
(ii) Oxidation of ethanol:
(iii) Hydrogenation of ethene:
(iv) Esterification reaction: Carboxylic acid + Alcohol
For example:
(v) Saponification reaction:
Ester
For example:
(iii) (a) The third homologue of alcohols is propanol, with the chemical formula
(b) The third homologue of aldehydes is propanal, with the chemical formula
(iv) (a) Benzene
(b) 'But-1-ene'
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