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CBSE Class 12 Chemistry 2013 Solved Paper

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Question : 9
Total: 30
18g of glucose, C6H12O6(. Molar Mass =180gmol−1) is dissolved in 1‌kg of water in a sauce pan. At what temperature will this solution boil?
(Kb. for water =0.52K‌kg‌mol−1, boiling point of pure water =373.15K )
Solution:  
ΔT=
Kb×WB×1000
mB×WA
ΔT=
0.52×18×1000
180×1000
=0.052
T−Tb=0.052
T−373=0.052
T=373+0.052
T=373.052K
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