CBSE Class 12 Chemistry 2014 Delhi Set 1 Solved Paper

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Question : 22
Total: 30
The following data were obtained during the first order thermal decomposition of SO2Cl2 at a constant volume: SO2Cl2(g) SO2(g)+Cl2(g)
 Experiment  Time /s1  Total pressure/atm
 1  0  0.4
 2  100  0.7
Calculate the rate constant.
(Given: long 4=0.6021,log2=0.3010 )
Solution:  
The given reaction is,
SO2Cl2(g) SO2(g)+Cl2(g)
Pi=0.4atm,P=0.7atm,t=100s
Thus, according to the integrated rate law for gas phase
K=
2.303
t
×log10
Pi
2PiP

K=2.303×102×log10
0.4
0.1

K=2.303×102×log10(4)
K=2.303×102×0.6021
K=1.3866×102 s1
Thus, the rate constant for the above reaction is 1.3866×102 s1.
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