CBSE Class 12 Chemistry 2016 Delhi Set 1 Solved Paper

© examsnet.com
Question : 13
Total: 26
The rate constant for the first order decompositon of H2O2 is given by the following equation :
log‌k=14.2−‌
1.0×104
T
K
‌;
‌

Calculate Ea for this reaction and rate constant k if its half-life period be 200 minutes.
(Given : R=8.314JK−1mol−1 )
Solution:  
log‌k=‌
log‌A−Ea
2.303‌RT
‌

‌
Ea
2.303‌RT
‌
=‌
1.0×104K
T

Ea‌=1.0×104×2.303×8.314
‌=191471.4J∕mol
t‌
1
2
‌
=‌
0.693
k

k‌=‌
0.693
200
‌min

‌=0.0034min−1
© examsnet.com
Go to Question: