CBSE Class 12 Chemistry 2016 Delhi Set 1 Solved Paper

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Question : 13
Total: 26
The rate constant for the first order decompositon of H2O2 is given by the following equation :
logk=14.2
1.0×104
T
K
;

Calculate Ea for this reaction and rate constant k if its half-life period be 200 minutes.
(Given : R=8.314JK1mol1 )
Solution:  
logk=
logAEa
2.303RT

Ea
2.303RT
=
1.0×104K
T

Ea=1.0×104×2.303×8.314
=191471.4Jmol
t
1
2
=
0.693
k

k=
0.693
200
min

=0.0034min1
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