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CBSE Class 12 Chemistry 2016 Outside Delhi Set 1 Solved Paper

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Question : 12
Total: 26
For the first order thermal decomposition reaction, the following data were obtained :
C2H5‌Cl(g)→C2H4(g)+HCl(g)
Time∕secTotal‌pressure∕atm
00.30
3000.50
Calculate the rate constant
(Given : log‌2=0.3010,log‌3=0.4771, log‌4=0.6021)
Solution:  
Given : Initial pressure,
P0‌=0.30‌atm
Pt‌=0.50‌atm
t‌=300 s
Rate constant, ‌k‌=‌
2.303
t
‌log‌
P0
2P0−Pt
=
2.303
300 s
‌log‌
0.30
2×0.30−0.50
‌=‌
2.303
300 s
‌log‌
0.30
0.60−0.50

‌=‌
2.303
300 s
‌log‌
0.30
0.10

‌=‌
2.303
300 s
‌log‌3
‌=‌
2.303
300 s
×0.4771
‌=‌
1.099
300 s

‌=0.0036 s−1
‌=3.6×10−3 s−1
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