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Question : 18
Total: 26
Give reasons for the following:
(i) Aniline does not undergo Friedal-Crafts reaction,
(ii)( CH 3 ) 2 NH is more basic than ( CH 3 ) 3 N in an aqueous solution,
(iii) Primary amines have higher boiling point than tertiary amines.
(i) Aniline does not undergo Friedal-Crafts reaction,
(ii)
(iii) Primary amines have higher boiling point than tertiary amines.
Solution:
(i) A Friedel Crafts reactions is carried out in the presence of AlCl 3 . But AICl 3 is used as catalyst and is acidic in nature whereas aniline is a strong base. Thus, aniline reacts with AICl 3 to form a salt. N -atom, electrophilic substitution in the benzene ring is deactivated. Hence, aniline does not undergo Firedel-Crafts reaction.
(ii)( CH 3 ) 2 NH is more basic than ( CH 3 ) 3 N in an aqueous solution. + I effect will increase in alkyl group that results in increasing the case of donation of lone pair electron. Amine accepts a proton and from cation which will be stabilised in water by solvation. Higher the solvation by hydrogen bonding, higher will be the basic strength.
(iii) In tertiary amines, there are noH -atoms whereas in primary amines, two H -atoms are present. Due to the presence of H -atoms, primary amines undergo extensive intermolecular H-bonding.
Due to the positive charge on the
(ii)
Therefore, with increase in methyl group, hydrogen bonding and stabilisation by solvation decreases. This net effect results in decreases of basic strength from secondary to tertiary amine.
(iii) In tertiary amines, there are no
As a result, extra energy is required to separate the molecules of primary amine. Therefore, primary amines have higher boiling point than tertiary amines.
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