CBSE Class 12 Chemistry 2016 Outside Delhi Set 1 Solved Paper

Question : 22

Total: 26

(a) For the complex [Fe(H2O)6]3+, write the hybridization, magnetic character and spin of the complex. (At. number: Fe=26 )
(b) Draw one of the geometrical isomers of the complex [Pt(en)2‌Cl2]2+ which is optically inactive.

Solution:

(a) [Fe(H2O)6]3+

Since H2O is a weak field ligand it cannot participate in pairing of electrons. Therefore, the number of unpaired electrons is 5 .
µ=√n(n+2)=√5(5+2) =√35=5.92‌BM.
Thus, it is strongly paramagnetic (due to presence of unpaired electrons).
In [Fe(H2O)6]3+, outer d-orbitals are used in hybridization and it is high spin or spin free complex.
(b) Geometrical isomer of [Pt(en)2‌Cl2]2+ which is optically active,

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