CBSE Class 12 Chemistry 2017 Delhi Set 2 Solved Paper

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Question : 7
Total: 10
Write the reactions involved in the following:
(i) Hell-Volhard-Zelinsky reaction
(ii) Decarboxylation reaction
Solution:  
(i) In Hell-Volhard-Zelinsky (HVZ) reaction, carboxylic acid having an α-hydrogen is halogenated at α-position on treatment with chlorine or bromine in the presence of red phosphorus to give α-halogenated carboxylic acid.
RCH2COOH
(i) X2RedP
(ii)H2O
RCHCOOH
|
X

(ii) In decarboxylation reaction, carboxylic acid loses CO2 to form hydrocarbons when their sodium salts are heated with sodalime (NaOH and CaO ) in the ratio 3:1.
RCOONa
NaOH and CaO
RH
+Na2CO3
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