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CBSE Class 12 Chemistry 2018 Solved Paper

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Question : 6
Total: 26
Calculate the freezing point of a solution containing 60g of glucose (Molar mass =180gmol−1 ) in 250g of water. (Kf of water =1.86K‌kg‌mol−1)‌‌2
Solution:  
∆Tf‌=Kfm
‌=Kf×‌
w2×1000
M2×w1

‌=‌
1.86×60×1000
180×250

‌=2.48K
∆Tf‌=Tfo−Tf
2.48‌=273.15−Tf
Tf‌=273.15−2.48=270.67K
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