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Question : 8
Total: 27
For a reaction,
2 H 2 O 2
2 H 2 O + O 2
the proposed mechanism is given below:
(1)H 2 O 2 + I − → H 2 O + IO − (slow)
(2)H 2 O 2 + IO − → H 2 O + I − + O 2 (fast)
(i) Write rate law of the reaction.
(ii) Write overall order of reaction.
(iii) Out of step (1) and (2), which one is rate determining step?
the proposed mechanism is given below:
(1)
(2)
(i) Write rate law of the reaction.
(ii) Write overall order of reaction.
(iii) Out of step (1) and (2), which one is rate determining step?
Solution:
(i) The rate law for the reaction is
rate = −
= k [ H 2 O 2 ] [ I − ]
(ii) This reaction is first order with respect to bothH 2 O 2 and I − .
The overall order of the reaction is bimolecular, 2. The order of the reaction is determined from the slowest step of the reaction mechanism.
(iii) The first reaction is slow, so this is the rate determining step.
(ii) This reaction is first order with respect to both
The overall order of the reaction is bimolecular, 2. The order of the reaction is determined from the slowest step of the reaction mechanism.
(iii) The first reaction is slow, so this is the rate determining step.
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