CBSE Class 12 Chemistry 2019 Outside Delhi Set 2 Solved Paper

© examsnet.com
Question : 25
Total: 27
SECTION - D

(a) Give equations of the following reactions:
(i) Phenol is treated with conc. HNO3.
(ii) Propene is treated with B2H6 followed by H2O2OH.
(iii) Sodium t-butoxide is treated with CH3Cl.
(b) How will you distinguish between butan-1-ol and butan-2-ol?
(c) Arrange the following in increasing order of acidity: Phenol, Ethanol, Water
OR
(a) How can you obtain Phenol from (i) Cumene, (ii) Benzene sulphonic acid, (iii) Benzene diazonium chloride?
(b) Write the structure of the major product obtained from dinitration of 3-methylphenol.
(c) Write the reaction involved in Kolbe's reaction.
Solution:  
(a) (i)

(ii)
(iii)
Na+O
CH3
|
C
|
CH3
CH3
+CH3Cl
CH3O
CH3
|
C
|
CH3
CH3
+NaCl

Sodium t-butoxide Chloromethane 2-Methoxy 2-Methyl propane

(b) Iodoform test: Butan 2ol (secondary alcohol) reacts with iodine and NaOH to give yellow precipitate of CHI3 (iodoform) whereas butan -1 -ol does not react with iodine and NaOH.
CH3CH2
OH
|
CH
CH
3
+4I2
+6NaOH
C2H5COONa+CHI3+5NaI+5H2O
(Chloroform)

OHCH2CH2CH2CH3 +I2+NaOH No reaction
OR

© examsnet.com
Go to Question: