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Question : 27
Total: 27
(a) The conductivity of 0.001 mol L − 1 acetic acid is 4.95 × 10 − 5 S cm − 1 . Calculate the dissociation constant if ∧ m o for acetic acid is 390.5 S cm mol − 1 .
(b) Write Nernst equation for the reaction at25 ∘ C :
2 Al ( S ) + 3 Cu 2 + ( aq ) → 2 Al 3 + ( aq ) + 3 Cu ( s )
(c) What are secondary batteries? Give an example.
OR
(a) Represent the cell in which the following reaction takes place:
2 Al ( s ) + 3 Ni 2 + ( 0.1 M ) → 2 Al 3 + ( 0.01 M ) + 3 Ni ( s )
Calculate its emf ifE ° cell = 1.41 V .
(b) How does molar conductivity vary with increase in concentration for strong electrolyte and weak electrolyte? How can you obtain limiting molar conductivity( ∧ m o ) for weak electrolyte?
(b) Write Nernst equation for the reaction at
(c) What are secondary batteries? Give an example.
OR
(a) Represent the cell in which the following reaction takes place:
Calculate its emf if
(b) How does molar conductivity vary with increase in concentration for strong electrolyte and weak electrolyte? How can you obtain limiting molar conductivity
Solution:
(If
(b)
(c) Batteries which are rechargeable
Example- Lead storage,
(a)
(b) When the concentration of weak electrolyte becomes very low, its degree of ionization rises. This increase leads to increase in the number of ions in the solution. Thus, the molar conductivity rises sharply of a weak electrolyte at low concentration. The molar conductivity of strong electrolyte decreases a bit with an increase in concentration. This is due to increase in interionic attraction due to higher number of ions per unit volume. On dilution, ions move apart, weakening interionic attractions and thus conductance increases.
Limiting molar conductivity for weak electrolytes is obtained by using Kohlrausch law of independent migration of ions.
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