CBSE Class 12 Chemistry 2019 Outside Delhi Set 3 Solved Paper

Question : 7

Total: 13

(a) Although both [NiCl4]2− and [Ni(CO)4] have sp3 hybridisation yet [NiCl4]2− is paramagnetic and [Ni(CO)4] is diamagnetic. Give reason. (Atomic no. of Ni=28 )
(b) Write the electronic configuration of d5 on the basis of crystal field theory when.
(i) ∆o<P and
(ii) ∆o>P

Solution:

(a) In [NiCl4]2−,Ni is in +2 oxidation state and each Cl−donates a pair of electron. So, Cl−acts as a weak ligand and does, not cause any forced pairing. Thus, electrons remain unpaired making it paramagnetic.

In [Ni(CO)4],Ni is in zero oxidation state and CO acts as a strong ligand causing forced pairing. Thus, no electron remains unpaired making it diamagnetic.
(b) (i) t2g‌3eg2
(ii) t2g‌5eg‌0

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