CBSE Class 12 Chemistry 2020 Outside Delhi Set 1 Solved Paper

Question : 29

Total: 37

The rate constant for the first order decomposition of N2O5 is given by the following equation : k=(2.5×1014 s−1)e(−25000K)∕T
Calculate Ea for this reaction and rate constant if its half-life period be 300 minutes.

Solution:

‌k=(2.5×1014l−1)e(−25000K)∕T
‌t1∕2=300‌ minutes ‌
‌‌

=25000K
‌Ea=25000×R×K
‌=25000×8.314JK−1mol−1×K
‌=207850Jmol−1=207.850‌KJ‌mol−1
‌t1∕2=‌

0.693

⇒K=‌

0.693

300

min−1
‌=0.231×10−2
‌=2.31×10−3min−1
‌

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