Explanation: Propene yields two products, however only one predominates as per Markovnikov's rule i.e., 2-bromopropane which on heating with aq. KOH gives secondary alcohol. Aq. KOH is alkaline in nature so it gives hydroxide ion which is a nucleophile. It replaces halide(bromide in this case) ion and form alcohols.

CH3−CH=CH2

Propene

+HBr‌────▸‌

CH3− Br | CH −CH3

2−bromopropane

‌ aq. ‌‌KOH

────▸

CH3−

OH

| CH

−CH3