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Question : 7
Total: 12
(a) Write any two consequences of Lanthanoid Contraction.
(b) Name the element of3 d series which exhibits the largest number of oxidation states. Give reason.
(b) Name the element of
Solution:
(a) The two consequences of lanthanide contraction are:
(i) Due to close similarity in electronic configuration and ionic radii, the lanthanides have identical chemical properties which makes their separation difficult.
(ii) Due to lanthanide contraction, the size ofLn 3 + ions decrease regularly with increase in atomic number. According to Fajan's rule, decrease in size of Ln 3 + ions increase the covalent character and decrease the basic character between Ln 3 + and OH − ion in Ln ( OH ) 3 . Since the order of size of Ln 3 + ions are La 3 + > Ce 3 + . . . > Lu 3 + .
(b) The element which shows largest number of oxidation states in3 d series is Manganese (Mn). It shows the following oxidation states + 2 , + 3 , + 4 , + 5 , + 6 and +7 . It is because it contains the maximum no. of unpaired e − s in the outermost shell, i.e., 3 d 9 4 s 2 .
(i) Due to close similarity in electronic configuration and ionic radii, the lanthanides have identical chemical properties which makes their separation difficult.
(ii) Due to lanthanide contraction, the size of
(b) The element which shows largest number of oxidation states in
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