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Question : 2
Total: 12
(a) Why on dilution the ∧ m of CH 3 COOH increases very fast, while that of CH 3 COONa increases gradually?
(b) What happens if external potential applied becomes greater thanE ∘ to be in subscript of electrochemical cell?
(b) What happens if external potential applied becomes greater than
Solution:
(i) On dilution ∧ m of CH 3 COOH increases very fast because it is a weak electrolyte and the number of ions also increases due to increase in the degree of dissociation (less than 1). However,in CH 3 COONa which is a strong electrolyte, the number of ions remains same but the intermolecular forces of attraction decreases and the degree of dissociation is equal to 1 . Thus, ∧ m increases gradually in case of CH 3 COONa .
(ii) If the external potential applied become greater thanE ∘ cell of electrochemical cell, then the reaction gets reversed and the electrochemical cell acts as an electrolytic cell and vice-versa.
(ii) If the external potential applied become greater than
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