CBSE Class 12 Chemistry 2022 Term 2 Delhi Set 3

© examsnet.com
Question : 2
Total: 12
(a) Why on dilution the m of CH3COOH increases very fast, while that of CH3COONa increases gradually?
(b) What happens if external potential applied becomes greater than E to be in subscript of electrochemical cell?
Solution:  
(i) On dilution m of CH3COOH increases very fast because it is a weak electrolyte and the number of ions also increases due to increase in the degree of dissociation (less than 1). However,in CH3COONa which is a strong electrolyte, the number of ions remains same but the intermolecular forces of attraction decreases and the degree of dissociation is equal to 1 . Thus, m increases gradually in case of CH3COONa.
(ii) If the external potential applied become greater than E cell of electrochemical cell, then the reaction gets reversed and the electrochemical cell acts as an electrolytic cell and vice-versa.
© examsnet.com
Go to Question: