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Question : 13
Total: 13
SECTION - D
(a) Write the number of unpaired electrons in (Atomic number of
(b) Complete the reaction mentioning all the products formed:
(c) Account for the following:
(i)
(ii) Copper has exceptionally positive
(iii)
Solution: 👈: Video Solution
(a) C r = 25 , [ A r ] 3 d 4 4 s 2 → Ground state structure
C r 3 + = [ A r ] 3 d 4
There are four unpaired electrons present inC r 3 + .
(b)C r 2 O 7 2 − + 3 H 2 S + 8 H + →
+
+
(c) (i) Electronic configuration-
M n = 25 , [ A r ] 3 d 5 4 s 2 → M n 2 + = [ A r ] 3 d 5 → donating 2 e −
F e = 26 , [ A r ] 3 d 6 4 s 2 → F e 3 + = [ A r ] 3 d 5 → donating 3 e −
Mn = after loosing 2 electron3 d orbital is half filled and M n 2 + is stable.
F e = After loosing three electrons 3 d orbitals is half filled and more stable. That's why, F e 3 + is stable at +3 oxidation state and M n 2 + is stable in +2 oxidation state.
(ii)E ° value of copper is +ve i.e, 0.34 V . This is due to presence of high enthalpy of atomization and low enthalpy of hydrogen which make it exceptionally positive.
(iii) Electronic configuration ofE u 2 + [ X e ] 4 f 7 6 s 2
It has the tendency to loose two electron and attain a stable half filled configuration. So, it oxidized by loosing 2 electrons and reduce to other species.
There are four unpaired electrons present in
(b)
(c) (i) Electronic configuration-
Mn = after loosing 2 electron
(ii)
(iii) Electronic configuration of
It has the tendency to loose two electron and attain a stable half filled configuration. So, it oxidized by loosing 2 electrons and reduce to other species.
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