CBSE Class 12 Chemistry 2023 Outside Delhi Set 1 Solved Paper

Question : 19

Total: 35

SECTION - B

The vapour pressure of pure liquid X and pure liquid Y at 25°C are 120 mm Hg and 160 mm Hg respectively. If equal moles of X and Y are mixed to form an ideal solution, calculate the vapour pressure of the solution.

Solution: 👈: Video Solution

X=120 mm Hg,PA=PA0.xA
Y=160 mm Hg,PB=PB0.xB
∵ When equal amount of X and Y are mixedxA+xB=1
Acc. to Raoutt's law
Ptotal =PA+PB
PA0,xA+P‌B0,xB
=(1−xB)PA0+xBPB0
PTotal =PA0+(PB0−PA0)xB
=120+(160−120)×1
PTotal =120+40
=160 mm Hg

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