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Question : 27
Total: 35
Answer any three of the following:
(a) Which isomer ofC 5 H 10 C 5 H 9 C l
(b) Arrange the following compounds in increasing order of reactivity towardsS N 2
2-Bromopentane, 1-Bromopentane, 2-Bromo-2methylbutane
(c) Why p-dichlorobenzene has higher melting point than those of ortho and meta-isomers?
(d) Identify A and B in the following:
(a) Which isomer of
(b) Arrange the following compounds in increasing order of reactivity towards
2-Bromopentane, 1-Bromopentane, 2-Bromo-2methylbutane
(c) Why p-dichlorobenzene has higher melting point than those of ortho and meta-isomers?
(d) Identify A and B in the following:
Solution: 👈: Video Solution
(a) The hydrocarbon is either alkene or cycloalkane. It does not react with chlorine in dark. Hence it cannot be alkene. Hence, it is cycloalkene. The compound is cyclopentane.
( C 5 H 10 )
(b) 2-Bromo-2-methylbutane< < 1
(c) It is due to greater symmetry of para-isomer that fits in the crystal better as compared to o & m-isomers.
Cyclopentane
(b) 2-Bromo-2-methylbutane
(c) It is due to greater symmetry of para-isomer that fits in the crystal better as compared to o & m-isomers.
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