CBSE Class 12 Chemistry 2023 Outside Delhi Set 1 Solved Paper

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Question : 33
Total: 35
SECTION - E
(a) (I) Account for the following:
(i) Eo value for Mn3+Mn2+ couple is much more positive than that for Cr3+Cr2+.
(ii) Sc3+ is colourless whereas Ti3+ is coloured in an aqueous solution.
(iii) Actinoids show wide range of oxidation states.
(II) Write the chemical equations for the preparation of KMnO4 from MnO2.
OR(b) (I) Account for the following:
(i) Transition metals form alloys.
(ii) Ce4+ is a strong oxidising agent.
(II) Write one similarity and one difference between chemistry of Lanthanoids and Actinoids.
(III)Complete the following ionic equation:
Cr2O72+2OH
(a) (I) (i) Because Mn3+ has the outer electronic configuration of 3d4 & Mn2+ has the outer electron configuration of 3d5. Thus the conversion is favourable.
However in case of Cr3+Cr2+ undergoes a change in outer configuration from 3d3 to 3d4 which is not stable.
(ii) Due to absence of unpaired electron Sc3+ is colourless and due to presence of one unpaired electron d-d transition takes place making Ti3+ coloured in nature.
(iii) It is due to comparable energies of 5f,6d and 7s orbitals.
(II) 2MnO2+4KOH+O2
Δ
2K2MnO4+2H2O
3K2MnO4
4HCl
2
KMnO4
+MnO2+2H2O+4KCl
OR (b) (I) (i) The atomic radii of the transition elements in any series are not much different from each other.
As a result they can very easily replace each other in the lattice and form alloys.
(ii) Ce4+ has the tendency to accept one electron to get the +3 oxidation state, hence Ce+4 is a good oxidising agent.
(II) In case of lanthonoids, differentiating electron enters in 4f orbital whereas in case of Actinoids it enters in 5f orbital.
They both have (3+) as their most common oxidation state.
(III) Cr2O72+2OH 2 CrO42+ H2 O
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