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Question : 33
Total: 35
SECTION - E
(a) (I) Account for the following: (i)
(ii)
(iii) Actinoids show wide range of oxidation states.
(II) Write the chemical equations for the preparation of
OR(b) (I) Account for the following:
(i) Transition metals form alloys.
(ii)
(II) Write one similarity and one difference between chemistry of Lanthanoids and Actinoids.
(III)Complete the following ionic equation:
Solution: 👈: Video Solution
(a) (I) (i) Because M n 3 + has the outer electronic configuration of 3 d 4 & M n 2 + has the outer electron configuration of 3 d 5 . Thus the conversion is favourable.
However in case ofC r 3 + ∕ C r 2 + undergoes a change in outer configuration from 3 d 3 to 3 d 4 which is not stable.
(ii) Due to absence of unpaired electronS c 3 + is colourless and due to presence of one unpaired electron d-d transition takes place making T i 3 + coloured in nature.
(iii) It is due to comparable energies of5 f , 6 d and 7 s orbitals.
(II)2 M n O 2 + 4 K O H + O 2
2 K 2 M n O 4 + 2 H 2 O
3 K 2 M n O 4
2 K M n O 4 + M n O 2 + 2 H 2 O + 4 K C l
OR (b) (I) (i) The atomic radii of the transition elements in any series are not much different from each other.
As a result they can very easily replace each other in the lattice and form alloys.
(ii)C e 4 + has the tendency to accept one electron to get the +3 oxidation state, hence C e + 4 is a good oxidising agent.
(II) In case of lanthonoids, differentiating electron enters in4 f orbital whereas in case of Actinoids it enters in 5 f orbital.
They both have( 3 + ) as their most common oxidation state.
(III)C r 2 O 7 2 − + 2 O H − ─ ─ ─ ─ ▸ 2 C r O 4 2 − + H 2 O
However in case of
(ii) Due to absence of unpaired electron
(iii) It is due to comparable energies of
(II)
OR (b) (I) (i) The atomic radii of the transition elements in any series are not much different from each other.
As a result they can very easily replace each other in the lattice and form alloys.
(ii)
(II) In case of lanthonoids, differentiating electron enters in
They both have
(III)
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