2 [

1	3
0	x

] + [

y	0
1	2

] = [

5	6
1	8

]
[

2	6
0	2x

] + [

y	0
1	2

] = [

5	6
1	8

]
[

2+y	6+0
0+1	2x+2

] = [

5	6
1	8

]
[

2+y	6
1	2(x+1)

] = [

5	6
1	8

]
On comparing the corresponding elements of the matrices on both sides, we get:
2 + y = 5 ⇒ y = 3
2(x + 1) = 8 ⇒ x = 3