CBSE Class 12 Math 2009 Solved Paper

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Question : 10
Total: 29
Write the value of the determinant |
234
568
6x9x12x
|
Solution:  
Δ = |
234
568
6x9x12x
|

R3
1
3x
R3

Δ = 3x |
234
568
234
|

Now , R1 = R3
∴ Δ = 0
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