CBSE Class 12 Math 2009 Solved Paper

© examsnet.com
Question : 3
Total: 29
If
1
0
(3x2+2x+k)
dx = 0 , find the value of k.
Solution:  
Given:
1
0
(3x2+2x+k)
dx =
[
3x3
3
+
2x2
2
+kx
]
01
= 0
[x3+x2+kx]01 = 0
⇒ [1 + 1 + k] = 0
⇒ k = - 2
© examsnet.com
Go to Question: