CBSE Class 12 Math 2011 Solved Paper

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Question : 14
Total: 29
Find the value of ‘a’ for which the function f defined as
f (x) =
{
asin
π
2
(x+1)
x0
tanxsinx
x3
x>0

is continuous at x = 0.
Solution:  
f (x) =
{
asin
π
2
(x+1)
x0
tanxsinx
x3
x>0

The given function f is defined for all x ∊ R.
It is known that a function f is continuous at x = 0, if
lim
x0
f (x) =
lim
x0+
f (x) = f (0)
lim
x0
f (x) =
lim
x0
[sain
π
2
(x+1)
]
= a sin
π
2
= a (1) = a
lim
x0+
f (x) =
lim
x0
tanxsinx
x3
=
lim
x0
sinx
cosx
sinx
x3

=
lim
x0
sinx(1cosx)
x3cosx
=
lim
x0
sinx.2sin2
x
2
x3cosx

= 2
lim
x0
1
cosx
×
lim
x0
sinx
x
×
lim
x0
[
sin
x
2
x
]
02

= 2 × 1 × 1 ×
1
4
×
lim
x
2
0
[
sin
x
2
x
2
]
2

= 2 × 1 × 1 ×
1
4
× 1 =
1
2

Now, f(0) = a sin
π
2
(0 + 1) = a sin
π
2
= a × 1 = a
Since f is continuous at x = 0, a =
1
2
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