[

a−b	2a+c
2a−b	3c+d

] = [

−1	5
0	13

]
Equating the corresponding elements, we get,
⇒ a - b = -1, 2a + c = 5, 2a - b = 0, 3c + d = 13
Now, consider the equations:
a - b = -1 and 2a - b = 0
Subtracting first equation from second, we get: a = 1