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Question : 21
Total: 29
Find the shortest distance between the lines
= ( 4
−
) + λ (
+ 2
− 3
) and
= (
−
+ 2
) + µ ( 2
+ 4
− 5
)
Solution:
The shortest distance is given by,
=|
|
A 2 − A 1 = (
−
− 2
) - ( 4
−
) = - 3
− 2
B 1 × B 2 = |
| = 2
−
( A 2 − A 1 ) . ( B 1 × B 2 ) = ( − 3
− 2
) . ( 2
−
) = - 6
| B 1 × B 2 | = √ 2 2 + 1 2 = √ 5
so shortest distance between two lines =|
| =
units
=
so shortest distance between two lines =
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