CBSE Class 12 Math 2019 Delhi Set 1 Solved Paper

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Question : 21
Total: 29
Solve the differential equation : xdyydx=x2+y2dx, given that y=0 when x=1.
OR
Solve the differential equation : (1+x2)
dy
dx
+2xy
4x2
=0
, subject to the initial condition y(0)=0.
Solution:  
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