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CBSE Class 12 Math 2020 Delhi Set 1 Solved Paper

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Question : 6
Total: 36
ABCD is a rhombus whose diagonals intersect at E. Then
→
EA
+
→
EB
+
→
EC
+
→
ED
 equals
Solution:     👈: Video Solution
Given ABCD is a rhombus and diagonals intersect at E
Since in a rhombus diagonals bisect each other
|
→
EA
|=|
→
EC
|‌ and ‌|
→
EB
|=|
→
ED
|
but since they are opposite to each other they are of opposite signs ⇒
→
EA
=−
→
EC
 and
→
EB
=−
→
ED

⇒
→
EA
+
→
EC
=
→
O

...(i) and
→
EB
+
→
ED
=
→
O

Add (1) and (2)
⇒
→
EA
+
→
EB
+
→
EC
+
→
ED
=
→
O
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