CBSE Class 12 Math 2020 Delhi Set 2 Solved Paper | Question 2

CBSE Class 12 Math 2020 Delhi Set 2 Solved Paper

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Question : 2

Total: 11

∫4x3x‌dx equals

‌
12x
log‌12
+C
‌
4x
log‌4
+C
(‌
4x⋅3x
log‌4⋅log‌3
)+C
‌
3x
log‌3
+C

Solution:

Let,
I=∫4x3x‌dx
⇒‌‌I=∫12x‌dx
⇒‌‌I=‌

12x

log‌12

+C
‌‌‌[∵∫ax‌dx=‌

ax

log‌x

+C]

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